Let Z 2 be an algebraic closure of Z 2 , and let , Z
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Let Z̅2 be an algebraic closure of Z2, and let α, β ∈ Z̅2 be zeros of x3 + x2 + 1 and of x3 + x2 + 1, respectively. Using the results of this section, show that Z2(α) = Z2(β).
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Because both the given polynomials are irreducible over Z 2 both Z 2 and Z 2 are extens...View the full answer
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