Show that 6 does not factor uniquely (up to associates) into irreducibles in Z[-5]. Exhibit two different

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Show that 6 does not factor uniquely (up to associates) into irreducibles in Z[√-5]. Exhibit two different factorizations.

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A First Course In Abstract Algebra

ISBN: 9780201763904

7th Edition

Authors: John Fraleigh

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Question Posted: Jan 11, 2023 04:43 AM

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Show that 6 does not factor uniquely (up to associates) into irreducibles in Z[-5]. Exhibit two different

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We have 6 2 3 1 51 5 The numbers 2 and 3 are both irreducible in Z5 because the equations a 2 5b 2 2 and a 2 5b 2 3 have no solutions in integers See ...View the full answer

A First Course In Abstract Algebra

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