In problem use Theorem 7 1 1 to find 1 f(t) f(t) 4t 2 5 sin 3t Theorem 7 1 1 1 (a) L 1 n n 1, 2, 3, s a (b) L t (c) L e k (d) L sin kt (e) L cos kt 5 k s k k (f) L sinh kt (g) L cosh kt s2 k2 s2 k2

Question: In problem use Theorem 7.1.1 to find [1]{f(t)}. f(t) = 4t 2 - 5 sin 3t Theorem 7.1.1 1 (a) L{1} = - n!

In problem use Theorem 7.1.1 to find ℒ [1]{f(t)}.

f(t) = 4t² - 5 sin 3t

Theorem 7.1.1

1 (a) L{1} = - n! n = 1, 2, 3, ... =-- s - a (b) L{t

1 (a) L{1} = - n! n = 1, 2, 3, ... =-- s - a (b) L{t"} (c) L{e"} k (d) L{sin kt} (e) L{cos kt} 5? + k? s? + k? k (f) L{sinh kt} (g) L{cosh kt} s2 k2 s2 k2

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