Differentiating (13) with respect to u, using (13) in the resulting formula, and comparing coefficients of u
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where n = 1, 2, . . . . This formula is useful for computations, the loss of significant digits being small (except near zeros). Try (14) out for a few computations of your own choice.
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(n + 1)Pn+1(x) = (2n + 1)xP,(x) – npn-1(x),
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Abbreviate 1 2xu u 2 U Differentiation of 13 with respect ...View the full answer
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