Question: Find all initial conditions such that (x 2 - x)y' = (2x - 1)y has no solution, precisely one solution, and more than one solution.

Find all initial conditions such that (x2 - x)y' = (2x - 1)y has no solution, precisely one solution, and more than one solution.

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By separation and integration Taking exponents gives the general solution ... View full answer

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