Question: Solve the following initial value problems. y' 1 = 2y 1 + 5y 2 Y' 2 = -1/2y 1 -3/2y 2 y 1 (0) =

Solve the following initial value problems.

y'1 = 2y1 + 5y2

Y'2 = -1/2y1 -3/2y2

y1(0) = -12, y2(0) = 0

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