Question: Solve 2 u = -Ï 2 y sin 1/3Ïx for the grid in Fig. 462 and u y (1, 3) = u y (2, 3)

Solve ˆ‡2u = -Ï€2y sin 1/3Ï€x for the grid in Fig. 462 and uy(1, 3) = uy(2, 3) = 1/2ˆš243, u = 0 on the other three sides of the square.

и%3D 9 3 P, P. 12 22 2 P21 и %3 0 - бу? и 11 -и, х 2 3 х и в 0

%3D 9 3 P, P. 12 22 2 P21 %3 0 - ? 11 -, 2 3 0

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