Question: What happens in Prob. 7 if we replace sin z by cos z = sin (z + 1/2)? Data from Prob. 7 Let D: 0
What happens in Prob. 7 if we replace sin z by cos z = sin (z + 1/2π)?
Data from Prob. 7
Let D: 0 ≤ x ≤ 1/2 π, 0 ≤ y ≤ 1; D* the image of D w = sin z; and Φ* = u2 - v2. under and What is the corresponding potential Φ in D? What are its boundary values? Sketch D and D*.
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