Proof that Let k, m N*. If(k,m) = 1, then kZ m = Z m andZ

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Proof that Let k, m ϵ N*. If(k,m) = 1, then kZm = Zm andZm[k] = 0. If k|m, say m = kd, then kZm ≅ zd andZm[k] ≅ zk.

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