Question: For f(t) = 42e t , find f'(1), f'(0), and f'(1). Graph f(t), and draw tangent lines at t = 1, t = 0, and
For f(t) = 4−2et, find f'(−1), f'(0), and f'(1). Graph f(t), and draw tangent lines at t = −1, t = 0, and t = 1. Do the slopes of the lines match the derivatives you found?
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ft 4 2e t so ft 2e t and f1 2e 1 0736 ... View full answer
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