Question: Suppose that the interval 0 x 1 is divided into 100 subintervals of width x = .01. Show that the following sum is

Suppose that the interval 0 ≤ x ≤ 1 is divided into 100 subintervals of width Δx = .01. Show that the following sum is close to 5/4.[2(.01) + (.01)]Ax + [2(.02) + (02)]Ax + + [2(1.0) + (1.0)]

[2(.01) + (.01)]Ax + [2(.02) + (02)]Ax + + [2(1.0) + (1.0)] A.x.

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