Question: Suppose that the interval 0 x 1 is divided into 100 subintervals with a width of x = .01. Show that the sum
Suppose that the interval 0 ≤ x ≤ 1 is divided into 100 subintervals with a width of Δx = .01. Show that the sum![[3e-0.01] Ax + [3e-0.02] Ax + [3e-0.03] Ax +. + [3e-] Ax](https://dsd5zvtm8ll6.cloudfront.net/si.question.images/images/question_images/1679/7/4/9/460641ef154994351679749414713.jpg)
[3e-0.01] Ax + [3e-0.02] Ax + [3e-0.03] Ax +. + [3e-] Ax is close to 3(1-e).
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