For the system shown in Fig. 8.17, compute the power delivered by the pump to the water
Question:
For the system shown in Fig. 8.17, compute the power delivered by the pump to the water to pump 50 gal/min of water at 60°F to the tank. The air in the tank is at 40 psig. Consider the friction loss in the 225-ft-long discharge pipe, but neglect other losses. Then, redesign the system by using a larger pipe size to reduce the energy loss and reduce the power required to no more than 5.0 hp.
Distribution tank 5 ft 1-in Schedule 40 pipe 212 ft Flow 25-in Schedule 40 pipe 3 ft
Step by Step Answer:
a b Increase the pipe size to 1 in Schedule 40 Results v 788 fts N R 874 10 4 D 895 f 00232 The...View the full answer
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An air pump is a device used to inflate or deflate objects by moving air in or out of them. There are many different types of air pumps, ranging from manual hand pumps to electrically powered pumps, and they are used for a variety of purposes. John had trouble blowing up many balloons without a balloon pump and experienced pain. He solved this problem by using an empty plastic bottle with a rectangular-shaped hole in the cap, a cut piece of balloon stretched over it, and a small hole in the bottle. By pressing and releasing the bottle, he created an air pump to inflate the balloons without any discomfort. Air pumps utilize fluid mechanics and thermodynamics principles to increase air pressure inside an object being inflated, such as a bicycle tire. The ideal gas law is used to calculate the pressure inside the tire. As air pressure increases, the object becomes more rigid and can support more weight. The efficiency of the pump is determined by how much of the work done is converted into useful work, such as inflating the tire, and how much is lost as heat. Understanding these principles is important to effectively use and optimize the use of air pumps.
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