In Problem 7.8 (Fig. 7.17), if the left-hand tank is also sealed and air pressure above the
Question:
In Problem 7.8 (Fig. 7.17), if the left-hand tank is also sealed and air pressure above the water is 68 kPa, calculate the pump power.
In Problem
A pump is being used to transfer water from an open tank to one that has air at 500 kPa above the water, as shown in Fig. 7.17. If 2250 L/min is being pumped, calculate the power delivered by the pump to the water. Assume that the level of the surface in each tank is the same.
Step by Step Answer:
P A h A w Q 44...View the full answer
Related Video
In this video, the concept of pressure has been explained. The bottle is filled up with water, remove the pipe, and now you can see the clear flow of water from the holes due to liquid pressure.You can see that the second layer is holding the weight of the first layer and the third layer holding the weight of both upper layers, that’s why liquid flows out wider from the third as compared to the first two.At the first hole, water doesn’t roll along the walls; it flows out at an angle.At the second hole, you’ll see that the water flows out at a wider angle as compared to the first hole.At the third hole, we can see that the flow of water is much wider/greater than the other holes.This proves that the pressure at the bottom of the bottle is much more than the pressure at the top layers. P = ????gh
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