Question: Prove that the most general solution to the functional equation (x) = 2 (2x) is (x) = (log 2 x)/x where (z + 1) =

Prove that the most general solution to the functional equation φ(x) = 2 φ(2x) is φ(x) = ƒ(logx)/x where ƒ(z + 1) = ƒ(z) is any 1 periodic function.

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Lets start by making a substitution let y log2 x Then we can rewrite the functional ... View full answer

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