Question: Suppose that a quality characteristic is normally distributed with specifications at 120 20. The process standard deviation is 6.5. (a) Suppose that the process

Suppose that a quality characteristic is normally distributed with specifications at 120 ± 20. The process standard deviation is 6.5.

(a) Suppose that the process mean is 120. What are the natural tolerance limits? What is the fraction defective? Calculate PCR and PCRk and interpret these ratios.

(b) Suppose that the process mean shifts off-center by 1.5 standard deviations toward the upper specification limit. Recalculate the quantities in part (a).

(c) Compare the results in parts (a) and (b) and comment on any differences.

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a The natural tolerance limits are 120 365 1005 1395 The fraction conforming is ... View full answer

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