Question: Suppose that a quality characteristic is normally distributed with specifications at 100 20. The process standard deviation is 6. (a) Suppose that the process
Suppose that a quality characteristic is normally distributed with specifications at 100 ± 20. The process standard deviation is 6.
(a) Suppose that the process mean is 100. What are the natural tolerance limits? What is the fraction defective? Calculate PCR and PCRk and interpret these ratios.
(b) Suppose that the process mean is 106. What are the natural tolerance limits? What is the fraction defective? Calculate PCR and PCRk and interpret these ratios.
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a The natural tolerance limits are 100 20 Since the process natural tolerance limits lie in... View full answer
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