Question: A triangular brace is designed such that sides meet at angles of 42.0 and 59.5, with the longest side being 5.00 cm longer than the
A triangular brace is designed such that sides meet at angles of 42.0° and 59.5°, with the longest side being 5.00 cm longer than the shortest side. What is the perimeter of the brace?
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To solve this problem we can use the law of sines which relates the angles of ... View full answer
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