Question: Solve the given problems. A TV screen is 52.3 in. wide and 29.3 in. high. The length of a diagonal (the dimension used to describe

Solve the given problems.

A TV screen is 52.3 in. wide and 29.3 in. high. The length of a diagonal (the dimension used to describe it—from one corner to the opposite corner) is found by evaluating

where w is the width and h is the height. Find the diagonal.

w + h,

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