Question: Taking into account the weight loss of fuel, the maximum velocity v m of a rocket is v m = u(ln m 0 ln

Taking into account the weight loss of fuel, the maximum velocity v_m of a rocket is v_m = u(ln m₀ − ln m_s) − gt_f, where m₀ is the initial mass of the rocket and fuel, ms is the mass of the rocket shell, tf is the time during which fuel is expended, u is the velocity of the expelled fuel, and g is the acceleration due to gravity. Solve for m₀.

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