Question: When an object is thrown upward with an initial velocity of v 0 (in ft/s) from an initial height of s 0 (in ft), its

When an object is thrown upward with an initial velocity of v0 (in ft/s) from an initial height of s0 (in ft), its height after t seconds is given by −16t2 + v0t + s0.  Find an expression for the height and write it in factored form.

v0 = 24 ft/s, s0 = 40ft

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The expression for the height of the object after t seconds is ht 16t2 ... View full answer

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