Question: When an object is thrown straight up into the air, Newton's Second Law of Motion states that its height s (t) at time t is
S(t) = s0 + v0t + 1/2gt2
where v0 is its initial velocity and g is the constant of acceleration due to gravity. Suppose we take the measurements shown in Table 7.6.
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(a) Find the least squares approximating quadratic for these data.
(h) Estimate the height at which the object was released (in m), its initial velocity (in m/s), and its acceleration due to gravity (in m/s2).
(c) Approximately when will the object hit the ground?
Table 7.6 Time (s) Height (m) 0.5 5 23 7 2 23 18
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