Suppose that your prior for is a 2/3 : 1/3 mixture of N(0, 1) and N(1,
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Suppose that your prior for θ is a 2/3 : 1/3 mixture of N(0, 1) and N(1, 1) and that a single observation x ~ N(θ, 1) turns out to equal 2. What is your posterior probability that θ > 1?
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To find the posterior probability that 1 given the observation x 2 we can use Bayes theorem Lets den...View the full answer
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