Question: Consider the efficiency of locating the kth element in a doubly-linked list of length n. If k > n/2, it is more efficient to start

Consider the efficiency of locating the kth element in a doubly-linked list of length n. If k > n/2, it is more efficient to start at the end of the list and move the iterator to the previous element. Why doesn’t this increase in efficiency improve the big-Oh estimate of element access in a doubly-linked list?

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Big Oh notation is used to describe the upper bound of the time complexity in the worstcase scenario ... View full answer

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