Question: In Exercises show that the two formulas are equivalent. [cotx dx cot x dx = In|sin x + C cot x dx = - In|csc

In Exercises show that the two formulas are equivalent.

[cotx dx cot x dx = In|sin x + C cot x

[cotx dx cot x dx = In|sin x + C cot x dx = - In|csc x| + C

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