Calculate the total mass of a metal tube in the helical shape (mathbf{r}(t)=left(cos t, sin t, t^{2}ight))
Question:
Calculate the total mass of a metal tube in the helical shape \(\mathbf{r}(t)=\left(\cos t, \sin t, t^{2}ight)\) (distance in centimeters) for \(0 \leq t \leq 2 \pi\) if the mass density is \(ho(x, y, z)=\sqrt{z} \mathrm{~g} / \mathrm{cm}\).
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The total mass is the following integral MintC sqrtz d ...View the full answer
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Rustia Melrod
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