Question: CBS Let (mathcal{S}) be the surface (z=ln left(5-x^{2}-y^{2}ight)) for (0 leq x leq 1,0 leq y leq 1). Using a computer algebra system: (a) calculate

CBS Let $\mathcal{S}$ be the surface $z=\ln \left(5-x^{2}-y^{2}ight)$ for $0 \leq x \leq 1,0 \leq y \leq 1$. Using a computer algebra system:
(a) calculate the surface area of $\mathcal{S}$ to four decimal places.
(b) calculate $\iint_{\mathcal{S}} x^{2} y^{3} d S$ to four decimal places.

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a Using that zx2 x left5x2y2ight and zy2 y left5x2y2ight we calculate n ... View full answer

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