Find the area of the portion of the plane (2 x+3 y+4 z=28) lying above the rectangle
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Find the area of the portion of the plane \(2 x+3 y+4 z=28\) lying above the rectangle \(1 \leq x \leq 3,2 \leq y \leq 5\) in the \(x y\)-plane.
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We rewrite the equation of the plane as zgx yfracx2frac34 ...View the full answer
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