Question: Figure 1 shows the slope field for dy/dt = sin y + ty. Sketch the graphs of the solutions with the initial conditions y(0) =

Figure 1 shows the slope field for dy/dt = sin y + ty. Sketch the graphs of the solutions with the initial conditions y(0) = 1 , y(0) = 0, and y(0) = −1.

2 1 0 -1 -2 y / 1 I I -2 -1 0 1 2

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