Question: Let 1 : D 1 D 2 and 2 : D 2 D 3 be C 1 maps, and let

Let Φ1 : D→ D2 and Φ2 : D→ D3 be C1 maps, and let Φ◦ Φ1 : D1 → D3 be the composite map. Use the Multivariable Chain Rule and Exercise 49 to show that

Jac(D0 D) = Jac()Jac()


Data From Exercise 49

The product of 2 × 2 matrices A and B is the matrix AB defined by

a b b' ( 5 ) ( 25 ) = C d A B aa' + bc' ca' + de' ab' + bd' cb' + dd' AB

The (i, j)-entry of A is the dot product of the ith row of A and the jth column of B. Prove that det(AB) = det(A) det(B).

Jac(D0 D) = Jac()Jac()

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