Question: Let g be the inverse of a function satisfying '(x) = '(x). Show that g'(x) = x 1 . This shows that the inverse

Let g be the inverse of a function ƒ satisfying ƒ'(x) = ƒ'(x). Show that g'(x) = x−1. This shows that the inverse of the exponential function ƒ(x) = eis an antiderivative of x−1. That inverse is the natural logarithm function that we define in the next section.

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