Question: Let (mathbf{E}) be the electric field due to a long, uniformly charged rod of radius (R) with charge density (delta) per unit length (Figure 21).

Let \(\mathbf{E}\) be the electric field due to a long, uniformly charged rod of radius \(R\) with charge density \(\delta\) per unit length (Figure 21). By symmetry, we may assume that \(\mathbf{E}\) is everywhere perpendicular to the rod and its magnitude \(E(d)\) depends only on the distance \(d\) to the rod (strictly speaking, this would hold only if the rod were infinite, but it is nearly true if the rod is long enough). Show that \(E(d)=\delta / 2 \pi \epsilon_{0} d\) for \(d>R\). Apply Gauss's Law to a cylinder of radius \(R\) and of unit length with its axis along the rod.

X E -R y Charged rod

X E -R y Charged rod

Step by Step Solution

3.37 Rating (169 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

To solve for the electric field Ed at a distance d from a long uniformly charged rod using Gausss La... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Calculus 4th Questions!