Question: Let (u) = u q and g(x) = x p/q . Assume that g is differentiable. (a) Show that (g(x)) = x p (recall the

Let ƒ(u) = uand g(x) = xp/q. Assume that g is differentiable.
(a) Show that ƒ(g(x)) = x(recall the Laws of Exponents).
(b) Apply the Chain Rule and the Power Rule for whole-number exponents to show that ƒ'(g(x)) g'(x) = pxp−1.
(c) Then derive the Power Rule for xp/q.

Step by Step Solution

3.41 Rating (167 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a Let u u q and gx x pq where q is a positive integer a... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Calculus 4th Questions!