This exercise proves the Chain Rule without the special assumption made in the text. For any number

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This exercise proves the Chain Rule without the special assumption made in the text. For any number b, define a new function

F(u): = f(u) - f(b) u-b for all u b

(a) Show that if we define F(b) = ƒ'(b), then F is continuous at u = b.
(b) Take b = g(a). Show that if x ≠ a, then for all u,

((v)8) - (n)f x-a = u - g(a) F(u)- D-X

Note that both sides are zero if u = g(a).

(c) Substitute u = g(x) in Eq. (1) to obtain

Eq.(1)

f(g(x + h))-f(g(x)) h f(g(x + h))-f(g(x)) g(x +h)- g(x) X g(x+h)- g(x) h

f(g(x))-f(g(a)) x-a F(g(x)) g(x) - g(a) x-a

Derive the Chain Rule by computing the limit of both sides as x → a.


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Related Book For  book-img-for-question

Calculus

ISBN: 9781319055844

4th Edition

Authors: Jon Rogawski, Colin Adams, Robert Franzosa

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