Question: Show that where F'(x) = (x) and G'(x) = F(x). Use this to evaluate [x x f(x) dx = xF(x) - G(x)

Show that

[x x f(x) dx = xF(x) - G(x)

where F'(x) = ƒ(x) and G'(x) = F(x). Use this to evaluatefxcos.xdx.

[x x f(x) dx = xF(x) - G(x)

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