Question: Show that work performed by a constant force field (mathbf{F}) over any path (C) from (P) to (Q) is equal to (mathbf{F} cdot overrightarrow{P Q}).
Show that work performed by a constant force field \(\mathbf{F}\) over any path \(C\) from \(P\) to \(Q\) is equal to \(\mathbf{F} \cdot \overrightarrow{P Q}\).
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We denote by mathbfrtxt yt ct t0 leq t leq t1 a parametrization of the oriented path from P to Q the... View full answer
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