Question: Show that (x) = 2x 3 + 2x + sin x + 1 has precisely one real root.

Show that ƒ(x) = 2x3 + 2x + sin x + 1 has precisely one real root.

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We have f0 1 and f1 3 sin1 384 0 Therefore f has a root in the interval 10 Now s... View full answer

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