Question: We investigate the binormal vector further. Follow steps (a)(c) to prove that there is a number called the torsion such that dB ds =

We investigate the binormal vector further.

Follow steps (a)–(c) to prove that there is a number τ called the torsion such that

dB ds = -TN dB dN (a) Show that = TX and conclude that dB/ds is orthogonal to T. ds ds (b) Differentiate B. B

dB ds = -TN dB dN (a) Show that = TX and conclude that dB/ds is orthogonal to T. ds ds (b) Differentiate B. B = 1 with respect to s to show that dB/ds is orthogonal to B. (c) Conclude that dB/ds is a multiple of N.

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a Using the Product Rule for cross product we have dB d TXN N XNTX ds ds dB ds ... View full answer

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