Question: A stone is launched vertically upward from a cliff 192 feet above the ground at a speed of 64 ft/s. Its height above the ground

A stone is launched vertically upward from a cliff 192 feet above the ground at a speed of 64 ft/s. Its height above the ground t seconds after the launch is given by s = -16t² + 64t + 192, for 0 ≤ t ≤ 6. When does the stone reach its maximum height?

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