Question: . A stone is launched vertically upward from a cliff 320 ft above the ground at a speed of 16 ft/s. Its height above the

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A stone is launched vertically upward from a cliff 320 ft above the ground at a speed of 16 ft/s. Its height above the ground t seconds after the launch is given by s = - 16t + 16t+ 320 for 0 st 5. When does the stone reach its maximum height? Find the derivative of s. s' = The stone reaches its maximum height at (Simplify your answer.) S.

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