Assume that y > 0 is fixed and that x > 0. Show that d/dx (ln xy)

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Assume that y > 0 is fixed and that x > 0. Show that d/dx (ln xy) = d/dx (ln x). Recall that if two functions have the same derivative, then they differ by an additive constant. Set x = 1 to evaluate the constant and prove that ln xy = ln x + ln y.

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Calculus Early Transcendentals

ISBN: 978-0321947345

2nd edition

Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

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