For what values of a does the sequence {n!} grow faster than the sequence {n an }?
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For what values of a does the sequence {n!} grow faster than the sequence {nan}? Stirling’s formula is useful: n! ≈ √2pn nne-n, for large values of n.
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First note that for a 1 we already know that n grows fast than n So if a 1 then nan n so that nan ...View the full answer
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Related Book For
Calculus Early Transcendentals
ISBN: 978-0321947345
2nd edition
Authors: William L. Briggs, Lyle Cochran, Bernard Gillett
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