Question: To prove that lim 0 (sin )/ = 1 when is measured in radians, the plan is to show that the right- and left-hand
To prove that limθ→0 (sin θ)/θ = 1 when θ is measured in radians, the plan is to show that the right- and left-hand limits are both 1.
(a) To show that the right-hand limit is 1, explain why we can restrict our attention to 0 (b) Use the figure to show that


arca of = = s sin 0, 2 0 area of sector OAP = 21 1 area of AOAT= tan 6. sin 9 cos B Q tan 8 A(1.0) X
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a To show that the righthand limit of sin as approaches 0 is 1 we can restrict our ... View full answer
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