Question: Find h'(1) if where g(0) = 2 and g'(0) = 3. h(x) = p3 + xg(x) 3x - 5

Find h'(−1) if


h(x) = p3 + xg(x) 3x - 5



where g(0) = 2 and g'(0) = −3.

h(x) = p3 + xg(x) 3x - 5

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