a Express 15sin 8 cos in the form Rsin( ) where R 0 and 0 90 Give the value of correct to 2 decimal places b Hence solve the equation 15sin 8 cos 3 for 0 360 ...

We want to express 15sin 8cos in the form Rsin We can do this by find ...

a. Express 15sin 8 cos in the form Rsin( ) where R > 0 and

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a. Express 15sinθ − 8 cosθ in the form Rsin(θ − α) where R > 0 and 0° < α < 90°.

Give the value of α correct to 2 decimal places.

b. Hence solve the equation 15sinθ − 8 cosθ = 3 for 0° < θ < 360°.

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Cambridge International AS & A Level Mathematics Pure Mathematics 2 & 3 Coursebook

ISBN: 9781108407199

1st Edition

Authors: Sue Pemberton, Julianne Hughes, Julian Gilbey

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Question Posted: Mar 14, 2023 07:17 AM

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a. Express 15sin 8 cos in the form Rsin( ) where R > 0 and

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Cambridge International AS & A Level Mathematics Pure Mathematics 2 & 3 Coursebook

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