a Show that the equation 4sin 4 14 19 cos 2 can be written in the form 4x 2 19x 5 0, where x sin 2 b Hence, solve the equation 4sin 4 14 19 cos 2 for 0 360 ...

a We are given the equation 4sin4 14 19 cos2 Using the trigonometric identity sin2 cos2 1 we c ...

a. Show that the equation 4sin 4 + 14 = 19 cos 2 can be

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a. Show that the equation 4sin⁴θ + 14 = 19 cos²θ can be written in the form 4x² + 19x − 5 = 0, where x = sin²θ.
b. Hence, solve the equation 4sin⁴θ + 14 = 19 cos²θ for 0° ≤ θ ≤ 360°.

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Cambridge International AS And A Level Mathematics Pure Mathematics 1 Coursebook

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Authors: Sue Pemberton, Julian Gilbey

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a. Show that the equation 4sin 4 + 14 = 19 cos 2 can be

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a We are given the equation 4sin4 14 19 cos2 Using the trigonometric identity sin2 cos2 1 we c...View the full answer

Cambridge International AS And A Level Mathematics Pure Mathematics 1 Coursebook

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