i. Show that the equation 2 tan2 sin2 = 1 can be written in the form 2

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i. Show that the equation 2 tan2θ sin2θ = 1 can be written in the form 2 sin4θ + sin2θ − 1 = 0.

ii. Hence solve the equation 2tan2θsin2θ = 1 for 0° ≤ θ ≤ 360°.

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