Question: Solve a. |4x 3| = 7 b. |1 2x|= 5 c. d. e. f. |2x + 7| = 3x 3x-2 5 = 4

Solve

a. |4x − 3| = 7

b. |1 − 2x|= 5

3x-2 5 = 4

|2x + 7| = 3x

3x-2 5 = 4

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a we need to consider two cases one for when the expression inside the absolute value is positive and one for when it is negative Case 1 4x 3 0 When 4... View full answer

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