Solve each equation for 0 360 a 2 tan 2 1 sec b 3 cosec 2 13 a cot c 2 cot 2 cosec 13 d cosec cot 2 sin e tan 2 3sec 0 f 3 sec 2 cosec ...

ANSWER a To solve this equation we can use the identity sec2 1 tan2 So we have 2tan2 1 sec 2tan2 1 1 tan2 tan2 1 tan 1 Therefore 45 225 b Using the id ...

Solve each equation for 0 < < 360. a. 2 tan 2 1 =

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Solve each equation for 0° < θ < 360°.

a. 2 tan² θ − 1 = secθ

b. 3 cosec² = 13 −a cotθ

c. 2 cot²θ− cosecθ = 13

d. cosec + cotθ = 2 sinθ

e. tan² θ + 3secθ = 0

f. √3 sec²θ = cosecθ

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Cambridge International AS & A Level Mathematics Pure Mathematics 2 & 3 Coursebook

ISBN: 9781108407199

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Authors: Sue Pemberton, Julianne Hughes, Julian Gilbey

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Solve each equation for 0 < < 360. a. 2 tan 2 1 =

Question:

Step by Step Answer:

ANSWER a To solve this equation we can use the identity sec2 1 tan2 So we have 2tan2 1 sec 2tan2 1 1 tan2 tan2 1 tan 1 Therefore 45 225 b Using the id...View the full answer

Cambridge International AS & A Level Mathematics Pure Mathematics 2 & 3 Coursebook

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