Question: Solve each equation for 0 < < 360. a. 2 tan 2 1 = sec b. 3 cosec 2 = 13 a
Solve each equation for 0° < θ < 360°.
a. 2 tan2 θ − 1 = secθ
b. 3 cosec2 = 13 −a cotθ
c. 2 cot2 θ− cosecθ = 13
d. cosec + cotθ = 2 sinθ
e. tan2 θ + 3secθ = 0
f. √3 sec2θ = cosecθ
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ANSWER a To solve this equation we can use the identity sec2 1 tan2 So we have 2tan2 1 sec 2tan2 1 1 tan2 tan2 1 tan 1 Therefore 45 225 b Using the id... View full answer
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