Question: a. Predict the complete screen analysis for Example 17-11. The stack of screens used the following Tyler mesh screens: (10,12,14,20,24,32,42,60,80). Example 17-11 b. How many

a. Predict the complete screen analysis for Example 17-11. The stack of screens used the following Tyler mesh screens: \(10,12,14,20,24,32,42,60,80\).

Example 17-11

Another evaporative crystallization of urea gave G = 0.0240 mm/h, t =

b. How many grams of undersized crystals are not collected?

Another evaporative crystallization of urea gave G = 0.0240 mm/h, t = 6.70 h, n = 9.390 x 107 # /(L mm), kv = 1.0, and Pcrystal = 1.33 g/ml. We screened a sample of 1.0 L of magma and collected crystals between sieves with Tyler mesh 20 (0.841 mm) and 24 (0.707 mm). A. Predict the weight of crystals collected between these two sieves. B. What is the median size (on a weight basis) of distribution? If all of the screens listed in Table 17-2 are used, between what screens will the median size be collected? TABLE 17-2. Tyler Screen sizes Tyler Screen Designation 10 Opening, mm Average Opening between Two Screens, Li, mm 1.68 1.545 12 1.41 1.30 14 14 1.19 1.095 16 1.00 0.9205 20 20 0.841 0.774 24 24 0.707 0.651 28 0.595 0.5475 32 32 0.500 0.460 35 0.420 0.387 42 442 0.354 0.3255 40 48 0.297 0.2735 60 60 0.250 0.230 65 0.210 0.1935 80 08 0.177 0.151 115 0.125 0.1065 170 0.088 0.0755 250 0.063 0.0535 325 0.044 0.0405 400 0.037

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